Integrand size = 12, antiderivative size = 45 \[ \int \log \left (c \left (a+b x^2\right )^p\right ) \, dx=-2 p x+\frac {2 \sqrt {a} p \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{\sqrt {b}}+x \log \left (c \left (a+b x^2\right )^p\right ) \]
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Time = 0.01 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2498, 327, 211} \[ \int \log \left (c \left (a+b x^2\right )^p\right ) \, dx=\frac {2 \sqrt {a} p \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{\sqrt {b}}+x \log \left (c \left (a+b x^2\right )^p\right )-2 p x \]
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Rule 211
Rule 327
Rule 2498
Rubi steps \begin{align*} \text {integral}& = x \log \left (c \left (a+b x^2\right )^p\right )-(2 b p) \int \frac {x^2}{a+b x^2} \, dx \\ & = -2 p x+x \log \left (c \left (a+b x^2\right )^p\right )+(2 a p) \int \frac {1}{a+b x^2} \, dx \\ & = -2 p x+\frac {2 \sqrt {a} p \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{\sqrt {b}}+x \log \left (c \left (a+b x^2\right )^p\right ) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00 \[ \int \log \left (c \left (a+b x^2\right )^p\right ) \, dx=-2 p x+\frac {2 \sqrt {a} p \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{\sqrt {b}}+x \log \left (c \left (a+b x^2\right )^p\right ) \]
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Time = 0.28 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.02
method | result | size |
default | \(x \ln \left (c \left (b \,x^{2}+a \right )^{p}\right )-2 p b \left (\frac {x}{b}-\frac {a \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{b \sqrt {a b}}\right )\) | \(46\) |
parts | \(x \ln \left (c \left (b \,x^{2}+a \right )^{p}\right )-2 p b \left (\frac {x}{b}-\frac {a \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{b \sqrt {a b}}\right )\) | \(46\) |
risch | \(x \ln \left (\left (b \,x^{2}+a \right )^{p}\right )+\frac {i {\operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right )}^{2} \operatorname {csgn}\left (i \left (b \,x^{2}+a \right )^{p}\right ) x \pi }{2}-\frac {i \pi x \,\operatorname {csgn}\left (i \left (b \,x^{2}+a \right )^{p}\right ) \operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right ) \operatorname {csgn}\left (i c \right )}{2}-\frac {i \pi x {\operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right )}^{3}}{2}+\frac {i \operatorname {csgn}\left (i c \right ) {\operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right )}^{2} x \pi }{2}+x \ln \left (c \right )+\frac {\sqrt {-a b}\, p \ln \left (-\sqrt {-a b}\, x +a \right )}{b}-\frac {\sqrt {-a b}\, p \ln \left (\sqrt {-a b}\, x +a \right )}{b}-2 p x\) | \(186\) |
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Time = 0.33 (sec) , antiderivative size = 107, normalized size of antiderivative = 2.38 \[ \int \log \left (c \left (a+b x^2\right )^p\right ) \, dx=\left [p x \log \left (b x^{2} + a\right ) + p \sqrt {-\frac {a}{b}} \log \left (\frac {b x^{2} + 2 \, b x \sqrt {-\frac {a}{b}} - a}{b x^{2} + a}\right ) - 2 \, p x + x \log \left (c\right ), p x \log \left (b x^{2} + a\right ) + 2 \, p \sqrt {\frac {a}{b}} \arctan \left (\frac {b x \sqrt {\frac {a}{b}}}{a}\right ) - 2 \, p x + x \log \left (c\right )\right ] \]
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Leaf count of result is larger than twice the leaf count of optimal. 100 vs. \(2 (44) = 88\).
Time = 2.01 (sec) , antiderivative size = 100, normalized size of antiderivative = 2.22 \[ \int \log \left (c \left (a+b x^2\right )^p\right ) \, dx=\begin {cases} x \log {\left (0^{p} c \right )} & \text {for}\: a = 0 \wedge b = 0 \\x \log {\left (a^{p} c \right )} & \text {for}\: b = 0 \\- 2 p x + x \log {\left (c \left (b x^{2}\right )^{p} \right )} & \text {for}\: a = 0 \\\frac {2 a p \log {\left (x - \sqrt {- \frac {a}{b}} \right )}}{b \sqrt {- \frac {a}{b}}} - \frac {a \log {\left (c \left (a + b x^{2}\right )^{p} \right )}}{b \sqrt {- \frac {a}{b}}} - 2 p x + x \log {\left (c \left (a + b x^{2}\right )^{p} \right )} & \text {otherwise} \end {cases} \]
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Time = 0.29 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00 \[ \int \log \left (c \left (a+b x^2\right )^p\right ) \, dx=2 \, b p {\left (\frac {a \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{\sqrt {a b} b} - \frac {x}{b}\right )} + x \log \left ({\left (b x^{2} + a\right )}^{p} c\right ) \]
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Time = 0.28 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.91 \[ \int \log \left (c \left (a+b x^2\right )^p\right ) \, dx=p x \log \left (b x^{2} + a\right ) + \frac {2 \, a p \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{\sqrt {a b}} - {\left (2 \, p - \log \left (c\right )\right )} x \]
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Time = 1.23 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.82 \[ \int \log \left (c \left (a+b x^2\right )^p\right ) \, dx=x\,\ln \left (c\,{\left (b\,x^2+a\right )}^p\right )-2\,p\,x+\frac {2\,\sqrt {a}\,p\,\mathrm {atan}\left (\frac {\sqrt {b}\,x}{\sqrt {a}}\right )}{\sqrt {b}} \]
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